question about liters [Archive] - SR20 Forum

: question about liters


xDennis
04-25-2002, 01:21 PM
hey guys, im a littel confused about the liters of a engine. i thought that if you take the block of say a 2.0 liter car and drop it into a big puddle of water :D it will occupy 2liters. But then there are stroker kits that will raise the liters of the engine forexample the tomie kit will raise the 2.0l to 2.2l with a larger crank i belive and some more things. but can someone explain to me this whole liters thing? thanks. :D:D

kpw97
04-25-2002, 01:54 PM
The liter in each cylinder is the total volume occupied between the top and bottom of piston travel (TDC and BDC). This equates to your displacement volume, V(d). The total volume for the engine (V(t)) is then simply this volume times the number of cylinders, n(c).

V(d)*n(c)= V(t)

It's a pretty simple equation. Now, I believe the stroker kits bore out the cylinder a bit and use a longer crank and connecting rod (I could be wrong about the exacts of these kits).

Hope that helps:D

Stiletto
04-25-2002, 02:00 PM
AFAIK, the liter measurement is a rounded number from the cubic centimeters (cc) measurement. 1000 cc = 1 liter (litre) which is about 61 cubic inches. the measurement comes from the amount of displacement the engine makes.

OnyxEros
04-25-2002, 02:12 PM
like they said
and...

Your engine is essencially an air pump (inefficient one, but that's another story) The liters are the amout of air that travels through, stroking or boring causes more air to pass through

help any?
O

Sr20kidD
04-25-2002, 02:20 PM
what they said

jomama
04-25-2002, 02:44 PM
Originally posted by kpw97
It's a pretty simple equation. Now, I believe the stroker kits bore out the cylinder a bit and use a longer crank and connecting rod (I could be wrong about the exacts of these kits).


i believe stroker kits only change the stroke of the piston travel. i could be wrong. the science behind the increase displacement via stroker kit is this:

the volume (V) of a cylinder is

V = pi * r^2 * h

where:
pi is pi
r is the radius of the cylinder
h is the height, or in this case, the stroke of the piston

thus, by increasing stroke, you increase h and thereby increase V, giving you more displacement!

sleeping 91ser
04-25-2002, 09:02 PM
also in most cases they just round it up like our motor isnt quite a 2.0 liter but it sounds better than a 1.998 liters.
Sean

Zak91SER
04-25-2002, 10:08 PM
And actually the 5.0 Mustang was never a 5.0, even with rounding... because it was 4948ccs, and that rounds down, not up, to 4.9 liters. :)

RySE-R 1
04-25-2002, 10:50 PM
Yes, but 4.9 Mustang just doesn't sound quite as good;) As far as stroker kits go, I think the one for ours just changes the crank and rod length. Don't know if it affects the piston top shape as well? I don't think so.

Rocketman
04-25-2002, 11:14 PM
Bore and Stroke on our engine is 8.6106 centimeters
So if you take the formula for the displacement of an engine as follows:

Displacement=pi/4*bore ^2*stroke*No. of cylinders

So we get 0.785398*74.14243236*8.6106*4
or about 2000 cubic centimeters......

so anyway there ya go with actual dimensions.
Actual displacement of the block (how much water it displaces) would actually be significantly higher.

The above formula was taken from the auto math handbook btw.
Excellent book if you need any automotive formulas.
Rick

jomama
04-26-2002, 09:04 AM
Originally posted by Rocketman

Displacement=pi/4*bore ^2*stroke*No. of cylinders

So we get 0.785398*74.14243236*8.6106*4
or about 2000 cubic centimeters......

The above formula was taken from the auto math handbook btw.
Excellent book if you need any automotive formulas.
Rick

ok, don't mean to be a math dork or anything but the first part of that formula is quite misleading. it's essentially the same as what i posted several posts up. as opposed to using (pi/4) * bore^2 to get the area of the piston top, it's probably easier to remember it this way. the bore is essentially the diameter of the piston. thus pi * (bore/2)^2 is the same as pi/4 * bore^2, where bore/2 is the radius.

Rocketman
04-26-2002, 07:44 PM
ok, don't mean to be a math dork or anything but the first part of that formula is quite misleading. it's essentially the same as what i posted several posts up. as opposed to using (pi/4) * bore^2 to get the area of the piston top, it's probably easier to remember it this way. the bore is essentially the diameter of the piston. thus pi * (bore/2)^2 is the same as pi/4 * bore^2, where bore/2 is the radius.

No problem man... its just a difference in how you draw it out.
Pi*r^2 versus pi/4*bore ^2

I just decided to copy the formula straight out of the book since i was beein lazy and didn't feel like breakin it down any further. Just wanted to give the guy an idea with actual numbers is all.

I suppose i could have used our formula but i just didn't think about it at the time......

Oh well....
No harm no foul
Rick